Answer:
fog = 2√(x-1) + 1
Domain = [1,
)
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1,
)
Answer:
If x + 1 is odd, then x is even.
Step-by-step explanation:
The converse of the statement ...
if P, then Q.
is ...
if Q, then P.
Here, we have P="x is even" and Q="x+1 is odd". The converse statement is ...
if x+1 is odd, then x is even.
The answer is 1.
2×3=6
6÷6=1
Answer:
D
Step-by-step explanation:
you can just find the value of y and try some number of x
i.e. if x = 0, both of them will be 0
x = 1
G(x) result is -2
F(x) result is 1
x= -1
G(x) result will be 2
F(x) result is -1
so from these we can prove that G(x) is bigger graph than F(x) but flip vertically by y axis
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