We are given
length of rectangular yard is x
so, 
width of rectangular yard is
so, 
We are given
the length of the enclosed yard is 50 feet
so, we get
now, we can plug x=50 and then we can find width
now, we can find total fencing length
so, total fencing length is
now, we can plug values
now, we are given
the cost of fencing is $13 per foot
so,
total cost = (cost of fencing)*(total fencing length)
we can plug values
So, Janice will spend $4030.........Answer
v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Answer: D, Y, X
<u>Step-by-step explanation:</u>
The (salad, sandwich) coordinates are as follows:
A: (0, 10)
B: (1, 8)
C: (2, 6)
D: (3, 4) MOST EQUAL AMOUNTS
E: (4, 2)
F: (5, 0)
X: (4, 8) OUTSIDE OF THE PRODUCTION LINE
Y: (1, 3) UNDER THE PRODUCTION LINE
One thing for sure it is not b,d,c its a
Answer:
a. k > 7
b. a < -21
c. h > 9
d. f < 301
Step-by-step explanation:
a. 2k + 7 > 21
2k > 14
k > 7
b. a/3 + 12 < 5
a/3 < -7
a < -21
c. 6h − 5 > 49
6h > 54
h > 9
d. f/7 − 9 < 34
f/7 < 43
f < 301
Hope this helps!
