The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is
To determine the average speed we use the formula,
where and
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
As the lines are not intersecting nor parallel, they must be skew.
Step-by-step explanation:
Question is incomplete, we consider the nearest match available online.
Parametric equations of two lines are:
L₁ : x=4t+2 , y = 3 , z =-t+1
L₂: x=2s+2 , y= 2s+5 , z = s+1
If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.
If lines are intersecting then parametric coordinates must be equal for some value of t and s.
Hence the lines are not intersecting nor parallel, they must be skew.