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bekas [8.4K]
4 years ago
11

OF THE SHAPES SHOWN 1/6 are triangles and 5/12 are pentagons. What fraction of the shapes are either triangles or pentagons. the

re are 5 pentagons, 2 triangles, 4 circles, and one rectangle * please show work *
A 1/3
B 3/8
C 7/12
D 2/3
Mathematics
1 answer:
Nata [24]4 years ago
7 0
C, the question asks for a fraction of shapes that 're either triangles or pentagons. Meaning all triangles and pentagons.there is 2 triangles and 5 pentagons. So in total there is 7 shapes. Overall there is 12 shapes. So the fraction will be 7/12. OR you could add the fractions 1/6 and 5/12. You would need to find a common denominator, which is 12. So multiply both parts if 1/6 by 2. It will make 2/12. And add 2/12 and 5/12. 2/12+5/12=7/12. The answer is C.
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The volume of triangular prims.
Nat2105 [25]

Check the picture below.

so we really have 2 equal triangles with 3 rectangles, so let's get the area of each and sum them up.

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4 0
2 years ago
A company logo is made up of a square and three identical triangles. What is the area of the logo? Enter your answer in the box.
telo118 [61]

I think it will be 91 cm because the area of the square is 49 and the area of the triangles is 14

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8 0
4 years ago
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Vikentia [17]
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4 years ago
What is the sum of ten terms of an infinite geometric series if the first term is 8 and the ratio is 1/2
xxTIMURxx [149]

Answer:

We use the formula:

S 10 = 8 · [(1/2)^9 - 1] / (1/2 - 1 );

Then, S 10 = 8 · ( 1/512 - 1 ) / ( 1/2 - 1 );

S 10 = 8 · ( - 511 / 512 ) / (-1 / 2 );

S 10 = ( - 511 / 64 ) · ( - 2 );

S 10 = + 511 / 32;

S 10 = 15.96;

Step-by-step explanation:


6 0
3 years ago
10x - 10y = 1 x = y - 3 solve the system of equations by substitution. a. (-29/20, 31/20) b. (1/2, 2/5) c. no solution d. coinci
Gekata [30.6K]
First you'd substitute x= y-3 in the first equation.

10(y-3) -10y= 1

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The y's cancel each other out, so you're left with -30= 1. That means there's no solution :)
8 0
3 years ago
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