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Nitella [24]
2 years ago
8

X^3 + 3x^2 -10x factor polynomial and find zero​

Mathematics
2 answers:
Fantom [35]2 years ago
7 0

Answer:

  1. x(x - 2)(x + 5)
  2. x = 0, x = 2, x = -5

Step-by-step explanation:

x^3 + 3x^2 - 10x

~Factor

x(x - 2)(x + 5)

Solve for the zero.

x(x - 2)(x + 5) = 0

We know that; x = 0, x - 2 = 0, and x + 5 = 0

x = 0

x - 2 = 0

x = 2

x + 5 = 0

x = -5

Best of Luck!

Rudiy272 years ago
3 0

Here we are provided with an polynomial of degree 3 and we have to factorise it first and then we have to compute it's zeroes.

Given Polynomial:

  • x³ + 3x² - 10x

Taking common x from all the 3 terms,

➝ x(x² + 3x - 10)

Factorising through Middle term factorisation,

➝ x(x² + 5x - 2x - 10)

➝ x{x(x + 5) - 2(x + 5)}

➝ x(x - 2)(x + 5)

Hence, Factorised !!

Now equating to 0 to find the zeroes of the poly.

➝ x(x - 2)(x + 5) = 0

That means,

  • x = 0
  • x - 2 = 0
  • x + 5 = 0

So, the zeroes of the polynomial is 0, 2 or -5

And we are done....

Carry On Learning !

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1. Calculate the simple interest over an amount of N$ 2500 that is invested for 3 years and 6 months at a rate of 7% pa.​
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Answer:

N$  612.5

Step by step explaination:

Given,

Principal or'P'=N$2500

Time or'n'=3 years & 6 months or 3.5 years

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Step-by-step explanation:

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2 years ago
What is the product? (9 t minus 4)(negative 9 t minus 4) negative 81 t squared minus 16 negative 81 t squared + 16 negative 81 t
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The product is negative 81 t squared + 16 ⇒ 2nd answer

Step-by-step explanation:

The product of two binomials (ax + b)(cx + d), where a, b, c, and d are constant

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  • Multiply (ax) by (d) and (b) by (cx) ⇒ ext-reams and nears
  • Add the two products ⇒ like terms
  • Multiply (b) by (d) ⇒ 2nd × 2nd

Let us find the product of (9 t - 4) and (-9 t - 4)

Multiply the 1st two terms

∵ (9 t)(-9 t) = -81 t²

Multiply the ext-reams

∵ (9 t)(-4) = -36 t

Multiply the nears

∵ (-4)(-9 t) = 36 t

Add the like terms

∵ -36 t + 36 t = 0

Multiply the 2nd two terms

∵ (-4)(-4) = 16

Write the answer

∴ (9 t - 4)(-9 t - 4) = -81 t² + 0 + 16

∴ (9 t - 4)(-9 t - 4) = -81 t² + 16

The product is  -81 t² + 16

Learn more:

You can learn more about the product of algebraic expressions in brainly.com/question/1617787

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