Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
30 minutes by bus
Step-by-step explanation:
Equation: b = bus
b = (65 - 5) / 2
b = 60/2
b = 30 mins
Please give Brainliest :)
Fx - fa÷x - ( aif x ÷ n (2.178282)) (a) = -2.718282a² fix²+ fnx² - afn ÷ nx
The correct answer is NO LINEAR FACTORS (option A ).
in this problem what you are really looking for is which of these sets is a pathagorean triple. That means it will solve the pathagorean theorem. (a sqaured + b squared = c squared) c is always going to be the largest number or the hypotenuse. if you plug all the number sets into the theorem, only one works and that is 7, 24, 25 which is your answer.