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Crank
3 years ago
8

What is the expected value of X

Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Answer:

sorry I don't know about this Question

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Locate the mean of 2046,971,3113,and 1850.
Debora [2.8K]
To find the mean, you have to add all the numbers then divide it by how many numbers there are.

In this case, you'll need to add all those numbers and divide it by 4.
2046+971+3113+1850=7980\\7980\div4=1995

The mean is 1995.
7 0
3 years ago
What is the mean of this dot plot?
Ivahew [28]
If my math is right the it’s 21.13

Work:

(17+18+18+19+20+21+21+21+22+22+22+22+
23+25+26)/15
6 0
3 years ago
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Petri did the following problem but got the wrong answer. She needs to correct her mistake and turn the problem back in.
zubka84 [21]

Answer:

she needs to subtract 5-3 first

Step-by-step explanation:

4 0
3 years ago
Which is not equal to 60%?
kobusy [5.1K]

Answer:

D. 10/50

Step-by-step explanation:

3/5 = 60%

12/20 = 60%

15/25 = 60%

10/50 = 20%

3 0
3 years ago
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Every day, a comes to the bus stop at the same time, and boards the first bus that arrives. the arrival of the first bus is an e
mylen [45]
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.

So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:

<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>

where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.

8 0
3 years ago
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