What is the expected value of X
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Answer:
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5) = 0.0768
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Mean of the Population (μ) = 2500 gallons
Standard deviation of the population (σ) =200 gallons
Let 'X' be a random variable in Normal distribution
Given X = 2800
<u><em>Step(ii):-</em></u>
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5)
= 0.5 - A(Z₁)
= 0.5 - A(1.5)
= 0.5 -0.4232 ( from normal table)
= 0.0768
<u><em>Conclusion</em></u>:-
The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month
P(X≥ 2800) = P(Z₁≥1.5) = 0.0768