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Artist 52 [7]
3 years ago
12

Simplify a. x + 9 over 5x b. x - 8 over x + 1 c. 6(x + 2) d. x + 3

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0

x2+9

5x2

Hope I could help! :)

Charra [1.4K]3 years ago
4 0

Given : \frac{4x^2 + 36}{4x}\times \frac{1}{5x}

\implies \frac{4(x^2 + 9)}{4x}\times\frac{1}{5x}

\implies \frac{x^2 + 9}{x}\times\frac{1}{5x}

\implies \frac{x^2 + 9}{5x^2}

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vodomira [7]

Answer:

correct

Step-by-step explanation:

3(4)-2(4)+8=12

12-8+8=12

12=12

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Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

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The designed life should be of 21,840 vehicle miles.

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