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Mamont248 [21]
3 years ago
9

Pls help me calculate the inverse of y equals 2x over x-7

Mathematics
1 answer:
NeTakaya3 years ago
5 0
Y = 2x/x-7

x = 2y/y-7

xy - 7x = 2y

-7x = 2y - xy

-7x = y(2-x)

y = -7x / 2-x

y = 7x / x-2


f-¹(x) = 7x / x-2

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<img src="https://tex.z-dn.net/?f=x%20%20%5Cdiv%203x%20-%202%20%3D%201%20%5Cdiv%203x%20-%204" id="TexFormula1" title="x \div 3x
Maurinko [17]

Hello from MrBillDoesMath!

Answer:

x = 1/2 (1 +\- i sqrt(23))

Discussion:

x \3x - 2 =   (x/3)*x - 2   =  (x^2)/3 - 2     (*)

1 \3x - 4   =  (1/3)x - 4                               (**)

(*) = (**)   =>

(x^2)/3 -2 = (1/3)x - 4        => multiply both sides by 3

x^2 - 6 = x - 12                 => subtract x from both sides

x^2 -x -6 = -12                   => add 12 to both sides

x^2-x +6  = 0

Using the quadratic formula gives:

x = 1/2 (1 +\- i sqrt(23))

Thank you,

MrB

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Marysya12 [62]
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