So what I did was I wrote down the problem 50 - 10x = 20.
The first step I did was take 50 and subtract it from both sides: 50 - 10x = 20
-50 -50
After that i cross out the so 50's and take 20 and subtract it to 50 which gave me -30. So when you write this down you rewrite it as: -10x = -30
Last step: take the -10 and divide it by both sides the cross out the two -10's cause it's going to be written as -30/-10 which would give you x = 3. So there is your answer, hope this helps. :)
~Shadow
Answer:
$7
Davon charges $7 per hour of rental
Answer:
B. 6i√6
General Formulas and Concepts:
<u>Algebra II</u>
- Imaginary Numbers: √-1 = i
Step-by-step explanation:
<u>Step 1: Define expression</u>
√-216
<u>Step 2: Simplify</u>
- Factor: √-1 · √216
- Simplify: i · 6√6
- Multiply: 6i√6
There is NO solution.
Cancel t on both sides (1/5 = 7/8).
Since 1/5 = 7/8, that doesn't make any sense so that is inapplicable ( So NO answer).
18.
-2(-9)+3
18+3
21
Explanation: -2(-9) When multiplying numbers that have both a negative sign, the answer is positive. Multiply normally.
19.
-6(-4)0
24(0)
0
Explanation: -6(-4) As I explained before, the answer would be positive.
24(0) Every number multiplied by 0 is 0.
20.
56+(-7)
49
Explanation: 56+(-7) Any problem like this is just basically going to be 56-7.
21.
-36+(-4)
-40
Explanation: -36+(-4) You are simply adding normally then adding the sign. This will only work if the signs are the same. (Signs are positive and negative.)
