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2 years ago

I need help, I don't get this.

Mathematics

1 answer:

salantis [7]2 years ago

3 0

Answer:11 question

Y=5

X=3

Perimeter =16cm

Step-by-step explanation:

2x-4= 2*3=6-4=2

Y-3 = 5-3=2

3x-5=3*3=9-5=4

Y-1=5-1=4

2*(3+5)

=2*8

=16

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A = 3 and c = 12 c/a =

Bess [88]

Answer:

4, because 12/3 is 4 cause 3×4=12

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3 years ago

A mountain climber on MT. Everest is at 29,035 ft above sea level . A stone at the bottom of th dead sea is at 1,349 below sea l

Lana71 [14]

29035 is to the right of 0.
-1349 is to the left of 0.

so, the distance between them:

29035 - (-1349) = 29035+1349 = 30384

7 0

3 years ago

Diane keeps her ribbons in a drawer. She has 3 white ribbons, 6 pink ribbons, 2 yellow ribbons, and 7 blue ribbons. Without look

Akimi4 [234]

Answer:

1/3

Step-by-step explanation:

She has 18 ribbons in total and she has 6 pink ribbons so she has a 6/18 chance or 1/3 chance of pulling a pink ribbon

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3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$