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GuDViN [60]
3 years ago
15

Given the two points (3, -1) and (5,3), explain how to write the equation of the line in slope intercept form.

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

give more detials

Step-by-step explanation:

krok68 [10]3 years ago
4 0
To write the equation of the line in slope intercept form, you would need to solve to find the slope. The slope in this case is 2. We know that because 3-(-1)/5-3= 4/2.

And then to find the y-int we would need to substitute the known values on the equation y=mx+b . Using the point (5,3) we can calculate the intercept. We do 3=2(5)+b. We get that b=-7.

Now in the end the equation in slope intercept form will be
y=2x-7
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<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20Trigonometry%7D" id="TexFormula1" title="\boxed{\sf Trigonometry}" alt="\bo
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Answer:

→x=√3

Step-by-step explanation:

tan^{-1} x+2cot^{-1} x=\frac{2\pi }{3} \\\\tan^{-1} x+2(\frac{\pi }{2}-tan^{-1} x)= \frac{2\pi }{3} \\\\-tan^{-1} x=\frac{2\pi }{3}-\pi \\\\-tan^{-1} x=-\frac{\pi }{3} \\\\tan^{-1} x=\frac{\pi }{3} \\\\x=tan\frac{\pi }{3} \\\\x=\sqrt{3}

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