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Juliette [100K]
3 years ago
12

An insulated jug holds 4.5 quarts of water. How many pints is that? Please answer!!

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0

You're talking about units of volume in the US "customary" system.

1 quart = 2 pints
2 quarts = 4 pints
3 quarts = 6 pints
4 quarts = 8 pints
4.5 quarts = 9 pints

It makes no difference what kind of container may surround the quarts,
or what substance may be in them.  The conversion of quarts to pints is
the same, even if the quarts are in outer space and totally empty.


Elenna [48]3 years ago
5 0
4.5 quarts = 9 pints

( Remember: <em><u>1 quart equals 2 pints</u></em>)


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2 years ago
What is 45.67 in expanded form? 40+5+0.6+0.07 or 40+0.5+0.06+0.007 or 40+5+0.6+0.007 or 4+5+0.06+0.007?
polet [3.4K]
It's right .
40+5+0.6+0.07

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3 years ago
Convert 28 inches to ___ feet and inches.<br><br> ?????????????
musickatia [10]

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2 feet and 33 inches

Step-by-step explanation:

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5 0
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Read 2 more answers
Calculus AB
wariber [46]
Assuming you mean
\lim_{x \to 4} \frac{\sqrt{x+5}-3}{4-x}

that means as x approaches 4

if we sub 0 for x we get
0/0
and intermitent form
use l'hopital's rule

so
take the derivitive of the top and bottom seperatly
l'hopitals rule is something like
if \lim_{x \to n} \frac{f(x)}{g(x)} results in 0/0 or -∞/∞ or∞/∞ then keep doing it until f(n)/g(n) gives a form that isn't intermitent

so

take derivitive of top and bottom
\dfrac{\frac{1}{2\sqrt{x+5}}}{-1}
now, if we subsitute 4 for x we get
\dfrac{\frac{1}{2\sqrt{4+5}}}{-1}=

\dfrac{\frac{1}{2\sqrt{9}}}{-1}=

\dfrac{\frac{1}{2(3)}}{-1}=

\dfrac{\frac{1}{6}}{-1}=

\dfrac{1}{-6}=\dfrac{-1}{6}
8 0
2 years ago
Please help!!!<br><br> i need help with this
goblinko [34]

Answer:

Step-by-step explanation:

Combine like terms. Like terms have same variable with same power

a) (2xy + 4x) + (15xy - 5x)  = <u>2xy + 15xy</u> +<u> 4x - 5x</u>

                                         = 17xy - x

b) (6a + 4b² - 3) + (3b² - 5) = 6a + <u>4b² + 3b²</u>  <u>- 3 - 5 </u>

                                           = 6a + 7b² - 8

c) (4x³ - 3x² +4x) + (8x² - 5x ) = 4x³ <u>- 3x² + 8x²</u>  <u>+ 4x - 5x</u>

                                               = 4x³  + 5x² - x

d) (7b - 6a  + 9y) - (12b + 5a - 2y) =

In subtraction, add the additive inverse of (12b + 5a - 2y)

additive inverse = - 12b  - 5a  + 2y

(7b - 6a  + 9y) - (12b + 5a - 2y) = 7b - 6a + 9y  -12b -5a + 2y

                                                   = 7b - 12b  -6a - 5a  + 9y + 2y

                                                   = -5b - 11a + 11y

e) (2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)

Additive inverse of  13x + 4x² + 5 - 6y = -13x + 4x² - 5 + 6y

(2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)= 2x² + 7x - 2 + 9y -13x - 4x² -5 +6y

                    = 2x² - 4x² + 7x -13x -2 - 5 + 9y + 6y

                    = -2x²  - 6x  - 7 + 15y

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2 years ago
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