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AURORKA [14]
3 years ago
7

Please help me with mathematics.​

Mathematics
1 answer:
aev [14]3 years ago
3 0

Answer:

1.A+B=2y²+3x-x²+3x²-y²=y²+3x+2x²

2.A-B=2y²+3x-x²-3x²+y²=3y²+3x-4x²

3.B+C=3x²-y²+5x²-3xy=8x²-3xy-y²

4.B-C=3x²-y²-5x²+3xy=3xy-2x²-y²

5.A+B+C=2y²+3x-x²+3x²-y²+5x²-3xy

=y²+3x+2x²+5x²-3xy=y²+3x-3xy+7x²

6.A+B-C=y²+3x+2x²-5x²+3xy=y²+3x+3xy-3x²

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Three brothers decided to share costs evenly. They bought a race track for $36.99 and a car for $18.99. How much did each brothe
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54 55.98÷3=18.66

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4 years ago
Determine if each function is linear or nonlinear. Drag each function into a box to correctly classify it. linear nonlinear y=6x
Lady bird [3.3K]
The linear functions are:
y = 6x - 2
x + y = 12
y = x

The non-linear functions are:
y = 3x³ + 5
y = x² - 33

Explanation:
Linear functions can be written in the form y = mx+b, where m is the slope and b is the y-intercept.  In linear functions, the x variable has at highest an exponent of 1.

The first equation, y = 6x - 2, is in slope-intercept form; it is linear.
The second equation, y = 3x³ + 5, has an x with an exponent greater than 1; it is non-linear.
The third equation, y = x² - 33, has an x with an exponent greater than 1; it is non-linear.
The fourth equation, x + y = 12, can be written as y=mx+b:
x+y=12
Subtract x from both sides:
x+y-x=12-x
y = -x+12

This is a <span><u><em>linear </em></u></span>function.

The <u>fifth </u>equation, y = x, is in the form y=mx+b; in this case, m=1 and b=0.  This is <u><em>linear</em></u>.
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4 years ago
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The grizzly bears heart would drop 20% during hibernation
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3 years ago
Keep getting this wrong
Minchanka [31]

Remember that the y-intercept is where the function has a value of x = 0 and the x-intercept is where the function has a value of y = 0. Thus, to find the x-intercept and y-intercept, we can substitute these values into the equation and solve for the other variable.


<u>x-intercept</u>

Since the x-intecept has a y-value of 0, we can substitute this into the function and solve for x.

0 = -2x - 3

  • Set up

3 = -2x

  • Add 3 to both sides

x = - \dfrac{3}{2}

  • Divide both sides by -2

The x-value of the x-intercept is -\frac{3}{2} and the y-value is 0, meaning that the x-intercept has coordinates \boxed{(-\frac{3}{2}, 0)}.


<u>y-intercept</u>

Since the y-intercept has a x-value of 0, we can substitute this into the equation and solve for y:

y = -2(0) - 3

  • Set up

y = -3

  • Multiply and simplify

The y-value of the y-intercept is -3, meaning that the y-intercept of the function is \boxed{(0, -3)}.

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3 years ago
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Pls send me questions on functions only
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Wym ? Like me send u functions ?
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