Please help me how many times can 3 go into 77

The measure of one angle is six more than half the measure of another angle. If the angles are complementary, find both measures

Snowcat [4.5K]

Answer:

The measures of the two angles are 34° and 56°

Step-by-step explanation:

* Lets explain how to solve the problem

- The complementary angles are the angles whose the sum

of their measures is 90°

- The measure of one angle is six more than half the measure

of another angle

- Let the measure of the second angle angle is x

∵ The measure of the 2nd angle is x

∵ The measure of the first angle is 6 more than the half of the

measure of the second angle

∴ The 1st angle is 6 + 1/2 x

∵ The two angles are complementary

∴ The sum of their measures is 90°

∴ x + (6 + 1/2 x) = 90

∴ (x + 1/2 x) + 6 = 90

∴ 3/2 x + 6 = 90

- Subtract 6 from both sides

∴ 3/2 x = 84

- Multiply both sides by

∴ 3x = 168

- Divide both sides by 3

∴ x = 56

∵ x is the measure of the 2nd angle

∴ The measure of the 2nd angle is 56°

∵ The measure of the 1st angle = 6 + 1/2 x

∵ x = 56

∴ The measure of the 1st angle = 6 + 1/2(56) = 34°

* The measures of the two angles are 34° and 56°

4 0

3 years ago

Is my answer correct or no? <br> ---> show explanation & details if i am wrong!!!

neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ $r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7$

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

If the distance is equal to the radius of the circle, then the point is on the circle
If the distance is greater than the radius, then the point is outside the circle
If the distance is less than the radius, then the point is inside the circle

∵ The distance = $\sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}$

∵ r = 7

∵ $7\sqrt{2}$ > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0

3 years ago

6.371 in lowest terms

kozerog [31]

Well you would have to round this 5 and above goes up. Since 1 is lower than 5 that would leave you at 6.37. 7 rounds up so that would change to 6.4. Lastly 4 would round down, So that would leave you with 6. Now 6 is the simplest form but if your looking for rounded to the nearest tenth the answer would be 6.4. If your looking for rounded to the nearest 100th place 6.37. But over all simplest form is 6.

5 0

3 years ago

Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please

Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1) 7x + 8y = 20

(2) 7x – 2y = 29 Subtract (2) from (1)

10y = -9 Divide each side by 10

(3) y = -⁹/₁₀ Substitute (3) into (1)

7x - 2(-⁹/₁₀) = 29

7x + 18/10 = 29 Subtract 18/10 from each side

7x = 29 - 18/10

7x = (290 - 18)/10

7x = 272/10 Divide each side by 7

x = 272/70

x = 136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

136/5 - 72/10 = 20

136/5 - 36/5 = 20

100/5 = 20

20 = 20

(2) 7(136/35) – 2(-⁹/₁₀) = 29

136/5 + 18/10 = 29

136/5 + ⁹/₅ = 29

145/5 = 29

29 = 29

5 0

3 years ago

Can any one help me with this problem

katrin [286]

Answer:

37.74 ft

Step-by-step explanation:

An angle and its opposite side are known

Sin (of the angle)= opposite/ hypotenuse

The hypotenuse is equal to the length of the ladder, therefore solve the hypotenuse

Sin (32)= 20/ hypotenuse

hypotenuse= 20/ Sin (32)

Sin (32)=0.5299

hypotenuse= 20/ 0.5299

37.74 ft

Hopefully this helps :)

3 0

3 years ago