All categories

3 years ago

Combine like terms 9+18s - 7s

2 answers:

8 0

To combine like terms you have to do 18s-7 which would give you 11s
Then you do nothing with the 9
So your answer would be 9+11s

katovenus [111]3 years ago

3 0

Answer: The answer is 9+11s :)

Step-by-step explanation:

Combine like terms

9+18s-7s

9=11s so I don't what you mean but in case you want to find s it will be

11 11

S=9/11

You might be interested in

The volume of a cube is V=s3 , where s is the length of one edge of the cube. What is the edge length s for each cube?

PolarNik [594]

Answer:

s = $\sqrt[3]{999} }$

Step-by-step explanation:

V = s^3

Plug in the given volume.

999 = s^3

Take the third root of both sides to cancel out the ^3.

$\sqrt[3]{999} }$ = s

4 0

3 years ago

Read 2 more answers

Solve the inequality 7x<5x-8

Aleksandr [31]

Minust 5x both sides
7x-5x<5x-5x-8
2x<-8
divide by 2 both sides
x<-4

6 0

3 years ago

7 a. 49 b. 98 c. 12 14 I need the area!!

sp2606 [1]

Answer:

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 (14)*7

A =49

3 0

3 years ago

Read 2 more answers

If you want points for freee.

romanna [79]

Answer:

WHA

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

jek_recluse [69]

Answer:

Choice B: $y = 2\, (x - 6)^{2} + 5$ .

Step-by-step explanation:

For a parabola with vertex $(h,\, k)$ , the vertex form equation of that parabola in would be:

$\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}$ .

In this question, the vertex is $(6,\, 5)$ , such that $h = 6$ and $k = 5$ . There would exist a constant $a$ such that the equation of this parabola would be:

$y = a\, (x - 6)^{2} + 5$ .

The next step is to find the value of the constant $a$ .

Given that this parabola includes the point $(7,\, 7)$ , $x = 7$ and $y = 7$ would need to satisfy the equation of this parabola, $y = a\, (x - 6)^{2} + 5$ .