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aniked [119]
3 years ago
6

roblem: Report Error A partition of a positive integer $n$ is any way of writing $n$ as a sum of one or more positive integers,

in which we don't care about the order of the numbers in the sum. For example, the number 4 can be written as a sum of one or more positive integers (where we don't care about the order of the numbers in the sum) in exactly five ways: \[4,\; 3 + 1,\; 2 + 2,\; 2 + 1 + 1,\; 1 + 1 + 1 + 1.\] So 4 has five partitions. What is the number of partitions of the number 7?
Mathematics
1 answer:
wel3 years ago
8 0

Answer:

There are 15 partitions of 7.

Step-by-step explanation:

We are given that a partition of a positive integer $n$ is any way of writing $n$ as a sum of one or more positive integers, in which we don't care about the numbers in the sum .

We have to find the partition of 7

We are given an example

Partition of 4

4=4

4=3+1

4=2+2

4=1+2+1

4=1+1+1+1

There are five partition of 4

In similar way  we are finding  partition of 7

7=7

7=6+1

7=5+2

7=5+1+1

7=3+3+1

7=3+4

7=4+2+1

7=3+2+2

7=4+1+1+1

7=3+1+1+1+1

7=2+2+2+1

7=3+2+1+1

7=2+2+1+1+1

7=2+1+1+1+1+1

7=1+1+1+1+1+1+1

Hence, there are 15 partitions of 7.

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Darya [45]

Answer: 25%

Step-by-step explanation:

A coin has Head and tail

Thd likelihood that he will make his next two penalty kicks is synonymous to having head and head

Which is 1/2 × 1/2 = 1/4

Converting this to percentages gives 1/4 × 100 = 25%

3 0
4 years ago
1 1/5 + 17/2 - 3/2 Helppppp
REY [17]

Answer:

\frac{82}{10}

Step-by-step explanation:

1\frac{1}{5} +\frac{17}{2} -\frac{3}{2}

→ Convert the mixed number into an improper fraction

\frac{6}{5} +\frac{17}{2} -\frac{3}{2}

→ Complete the takeaway operation

\frac{6}{5} +\frac{14}{2}

→ Make the denominators the same

\frac{12}{10}+\frac{70}{10}

→ Simplify

\frac{82}{10}

7 0
3 years ago
There is no prior information about the proportion of Americans who support the gun control in 2018. If we want to estimate 99%
Romashka-Z-Leto [24]

Answer: 13

Step-by-step explanation:

If the prior population proportion is unavailable then the formula to find the sample size is given by :-

n=0.25(\dfrac{z^*}{E})^2

, where z* = Critical z-value

E = margin of error

Let p be the proportion of Americans who support the gun control in 2018.

As per given , we have

Confidence level = 99%

The critical z-value for 99% confidence interval is 2.576  ( BY z-table)

Margin of error : E= 0.36

Since there no  prior information about the proportion of Americans who support the gun control in 2018.

So , the required sample size  to estimate 99% confidence interval would be:

n=0.25(\dfrac{2.576}{0.36})^2=0.25(7.16)^2

n=0.25(51.2656)=12.8164\approx13

Hence,  13 Americans should be surveyed.

3 0
3 years ago
Which function represents the graph?
dexar [7]
Answer is number 2
I hope this helps you
7 0
3 years ago
Read 2 more answers
Marco wants to build house. United Building Company is offering the rate of $15.75 per square foot + an additional conference fe
marishachu [46]
Let us take the case of United Building Company First
Rate per square foot = $15.75
Conference fee taken per hour = $45.99
Total conferencing hours = 4 hours and 15 minutes
                                         = 4.15 hours
Total square feet of the house = 12226 square feet
Then
The total cost taken by the company = (15.75 * 12226) + ( 45.99 * 4.15) dollars
                                                            = 192559.5 + 190.86 dollars
                                                            = 192750.36 dollars
So the total amount taken by United Building Company is $192750.36 dollars
Now let us take the case of American Contracting Company
Rate per square foot taken = $12.46
Flat conferencing fee taken = $230
Then
The total cost taken by the company = (12.46 * 12226) + 230
                                                           = 152335.96 + 230 dollars
                                                           = 152565.96 dollars
So the total cost taken by the American Contracting Company is $152565.96.
8 0
3 years ago
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