X = number of cds on the rack
x + 7 = 30
x = 30 - 7
x = 23 <== so there are currently 23 cds on the rack
You have to label it but try 1 and 1/4, -1 and 1/4,2, and -2
Step-by-step explanation:
Perfect number is the positive integer which is equal to sum of proper divisors of the number.
Aliquot part is also called as proper divisor which means any divisor of the number which isn't equal to number itself.
<u>Number : 6 </u>
Perfect divisors / Aliquot part = 1, 2, 3
Sum of the divisors = 1 + 2 + 3 = 6
Thus, 6 is a perfect number.
<u>Number : 28</u>
Perfect divisors / Aliquot part = 1, 2, 4, 7, 14
Sum of the divisors = 1 + 2 + 4 + 7 + 14 = 28
Thus, 28 is a perfect number.
Answer:
Step-by-step explanation:
It can't be 102. If that happened 51 would be printer and you would never have gotten out of 51. It would keep on printing 51.
For the reason just given, 51 was not the starting point. It would just keep on printing 51.
D is obviously wrong because A and B are wrong.
The answer is C
204 is even. It will be divided by 2
102 is then printed out.
You always either divide the equation or multiply the equation
hope this helps
