The width of a rectangle is 8 inches more than the length. The perimeter is 60. Find the length and width of the rectangle

1 answer:

8 0

Perimeter is 2L+2W so we can say 2L+2W=60

The width is 8 inches more than the length so W=L+8.

Substitute our expression for W into the equation so all the terms are the same
2L + 2(L+8)=60
2L+2L+16=60
4L+16=60
4L=44
Length=11 inches
Width= 11+8 = 19 inches

We can prove this answer is right by doing 11 + 11 + 19 + 19 which equals 60

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