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djverab [1.8K]
3 years ago
5

4x-5y=23 y=-3x+3 how do i do this

Mathematics
1 answer:
sattari [20]3 years ago
7 0
So to start off you will need to substitute the Y into the equation. As shown in step one. Next you will need to solve for the parentheses by multiplying the 5 into the equation as shown in step 2. Once you do this you should get “ 4x +15x - 15 = 23. Next you will need to combine like terms! As shown in step 3. Next you will need to get rid of the 15 therefore you will add 15 from both sides as shown in step 4. By now you should get 19x= 38. Finally you will need to divide both sides by 19 as shown in step 5 and you will get the answer for x=2. Now that you have the number for x you will go back and substitute it back into the original problem as shown in step 6. Next you need to get rid of the 8 so you will subtract 8 from both sides as shown in step 7. After this you should have -5y=15. Next you will divide both sides by -5 to get the answer to “y” as shown in step 8. After this you should get your final answer as “ x=2 and y= -3


I hope this helps!!!!

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asambeis [7]

Answer: x=4, x=-5

Step-by-step explanation:

\frac{x}{x-4}-\frac{4}{x+5}=\frac{36}{x^2+x-20}

Multiply everything by the LCM = (x-4)(x+5):

\frac{x}{x-4}\left(x-4\right)\left(x+5\right)-\frac{4}{x+5}\left(x-4\right)\left(x+5\right)=\frac{36}{x^2+x-20}\left(x-4\right)\left(x+5\right)

\frac{x\left(x-4\right)\left(x+5\right)}{x-4} -\frac{4\left(x-4\right)\left(x+5\right)}{x+5} =\frac{36\left(x-4\right)\left(x+5\right)}{\left(x-4\right)\left(x+5\right)}

Simplify by cancelling out same terms: in the numerators and denominators:

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x^2+x-20=0

(x+5)(x-4) = 0

The solution to the quadratic equation is x=4, x=-5

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