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Sveta_85 [38]
3 years ago
15

Find the equation of the line

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0
Y=(6/7)x - 1/2 (where 1/2 is the y intercept and 6/7 is the slope)
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$20.00

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Olivia’s family is driving a total of 480 miles for a trip. They would like to complete the drive in 8 hours. What is the averag
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The front of a garage needs to be painted. The total area except for the door will be painted. The door is 1.5 m high and 2 m wi
Sever21 [200]

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The answer for A is 7.85m^{2}.

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Step-by-step explanation:

A-

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8 0
3 years ago
6x^2-9x +2=0 solve the quadratic equation using the quadratic formula
balu736 [363]

<u>ANSWER: </u>

The roots of 6 x^{2}-9 x+2=0 are \frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}

<u>SOLUTION:</u>

Given, quadratic equation is 6 x^{2}-9 x+2=0 --- eqn (1)

We need to find the roots of given quadratic equation using quadratic formula.

Quadratic formula for general quadratic equation  a x^{2}+b x+c=0 is X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for eqn (1) a = 6, b= -9 and c = 2

X=\frac{-(-9) \pm \sqrt{(-9)^{2}-4 \times6 \times 2}}{2 x 2}

X=\frac{9 \pm \sqrt{81-48}}{4}

\begin{array}{l}{X=\frac{9 \pm \sqrt{33}}{4}} \\ {X=\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}}\end{array}

Hence the roots of 6 x^{2}-9 x+2=0 are \frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}

6 0
3 years ago
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