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3 years ago

2x^2 + 28x - 96 ac method

Mathematics

1 answer:

g100num [7]3 years ago

5 0

I think the answer is 2(x2+14x−48)

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On average Asia makes 14 out of 20 free throws Assuming the relationship is proportional, how many free throws is she likely to

dybincka [34]

Answer:

105

Step-by-step explanation:

14:20=7:10

150/10=15

7x15=105

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3 years ago

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larisa [96]

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Step-by-step explanation:

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3 years ago

Determine the line symmetry for figure.

mel-nik [20]

Answer:

where's the problem

Step-by-step explanation:

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3 years ago

Determine if the two figures are congruent and explain your answer using transformations.

Maslowich

The coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

The given figures are quadrilaterals, in order to determine whether they are similar, we need to check if they are reflections of each other.

For the Quadrilateral ABCD, the coordinate of A is at A(-1, 1) and for the Quadrilateral DEFG, the coordinate of E is at E(1, 1).

Note that if an object is reflected over the y-axis the transformation is (x, y)->(-x, y)

We need to check whether if we reflect the coordinate A over the y-axis we will get coordinate E

Since the coordinate A(-1, 1) reflected over y-axis is (1, 1) is the coordinate of E, hence the two figures are congruent

Learn more on reflections here:brainly.com/question/1908648

7 0

3 years ago

A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,

Flura [38]

Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

Step(i):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 20-1=19

t₀.₉₅ = 1.729

$M.E = \frac{1.729 X10 }{\sqrt{20} }$

Margin of error = 3.866

Step(ii):-

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

Given another sample size n =30

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 30-1=29

t₀.₉₅ = 1.70

$M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24$

Margin of error = 3.24

5 0

3 years ago