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Mrrafil [7]
3 years ago
5

Can someone help out​

Mathematics
2 answers:
Lapatulllka [165]3 years ago
4 0

Answer: was there a total number of people?

Step-by-step explanation:

valentinak56 [21]3 years ago
4 0

Answer:

1720

Step-by-step explanation:

so 45 percent were supporting visiting team

100 is the total

100-45=55

55 percent=people supporting home team

55%=946 people

946/55

17.2=1%

so multiply 17.2 times 45

774 supported visiting team

to find total add 774+946 or multiply 17.2 times 100

1720

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Write equations for the vertical and horizontal lines passing through the point (-8,6)
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Answer:

x= -8  y=6  

Step-by-step explanation:

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What is the interquartile range?<br><br> The interquartile range is ____
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THE ANSWER IS THREE sorry cap lock

Step-by-step explanation:

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Help me from 6-9 (geometry)
elena55 [62]

Answer:

6) Two angles are called supplementary when their measures add up to 180 degrees. For example, two right angles are supplementary angles.

7) When the sum of two angles is equal to 90 degrees, they are called complementary angles. For example, 30 degrees and 60 degrees are complementary angles.

8) you have to plot the points on the graph and draw a line and label it with L at one point and M at another point.

9) x = 20

m < A = 65

m < B = 25

Step-by-step explanation:

9)

3x + 5 + 2x - 15 = 90

3x + 2x + 5 - 15 = 90

5x - 10 = 90

5x - 10 + 10 = 90 + 10

5x = 100

5 / 5x = 100 / 5

x = 20

A = 3x + 5

A = 3(20) + 5

A = 60 + 5

A = 65

B = 2x - 15

B = 2(20) - 15

B = 40 - 15

B = 25

8 0
2 years ago
How do you make the colored lines short enough to make a "K"?
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3 years ago
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
2 years ago
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