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kaheart [24]
3 years ago
7

NEED ANSWER FAST PLEASE HELP!!!

Mathematics
1 answer:
viktelen [127]3 years ago
6 0

Answer:

D

Step-by-step explanation:

plug in the coordinates for x and y

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f(x)=(x+3)(x-4) and g(x)=1/3(x+3)(x-4). the graphs of each are shown here. Which graph represents which polynomial function? exp
zvonat [6]

This is about interpretation of quadratic equation graphs.

<u><em>- The parabola that is continuous represents f(x) = (x+3)(x-4)</em></u>

<u><em>- The parabola that is a broken line represents g(x) = 1/3(x+3)(x-4)</em></u>

<u><em>- This is because calculating their y-intercept respectively corresponds with what is on the graph.</em></u>

  • We are given;

a) f(x) = (x+3)(x-4)

Let us confirm the x-intercept.

x-intercept here is when y = 0.

Thus, at y = 0; x + 3 = 0 and x - 4 = 0

Thus, at y = 0; x = -3 and y = 4

  • Let's now find the y-intercept;

y-intercept occurs when x = 0

Thus; y - intercept = (0 + 3)(0 - 4)

y - intercept = -12

  • Looking at the graph given, the only one that has it's y-intercept as -12 is the graph that has a continuous line.

  • This means the other graph that has dashed line would represent the other polynomial g(x)=1/3(x + 3)(x - 4)

Read more at; brainly.in/question/18896888

4 0
2 years ago
HELP!!!
MakcuM [25]

Answer:

based on my experience mind you're answer.

8 0
1 year ago
A=1+Prt solve for p
lilavasa [31]

A=1+Prt\\\\Prt=A-1\\\\P=\dfrac{A-1}{rt}

4 0
3 years ago
Please help I will mark brainlest
spin [16.1K]

Hope this helps, pls mark me brainliest

4 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
3 years ago
Read 2 more answers
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