Answer:
Area of a trapezium = 1/2(a+b)×h
where a and b are parallel sides of the trapezium
h is the height
First question
We must first find the height of the trapezium using Pythagoras theorem
That's
h² = 8² -3²
h =√ 64 - 9
h = √ 55m
a = 7m
b = 10+3 = 13m
Area of the trapezoid = 1/2(7+13)×√55
= 1/2×20×√55
= 74.16
= 74m² to the nearest tenth
Second question
We use sine to find the height
sin30° = h/12
h = 12 sin 30°
h = 6 in
Let the other half of the parallel side be x
To find the other half of the parallel side we use Pythagoras theorem
That's
x² = 12²- 6²
x = √144-36
x = √108
x = 6√3 in
So for this trapezoid
a = 9 in
b = (9 + 6√3) in
h = 6 in
Area of the trapezoid = 1/2(9 + 9+6√3) × 6
= 1/2(18+6√3)×6
= 85.176 in²
= 85 in² to the nearest tenth
Hope this helps you
Answer:
85
Step-by-step explanation:
Answer:
nine below zero
nine less than zero
the opposite of 9
Step-by-step explanation:
(brainliest plz)
Answer:
−4 cot(−45) csc(6) sin(330)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
5+0.29
