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stellarik [79]
3 years ago
6

Which of the following is equivalent to 19L

Mathematics
2 answers:
777dan777 [17]3 years ago
6 0

Answer:

19 L= 19000 mL

hope this helps

have a good day :)

Step-by-step explanation:

valkas [14]3 years ago
4 0

Answer:

There are no options to pick

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A random sample of the amounts for 22 purchases was taken. The mean was ​$42.97​, the standard deviation was ​$22.82​, and the m
Illusion [34]

Answer: a) 84 and b ) 2084

Step-by-step explanation:

Given : Sample standard deviation : s= $22.82

(Population standard deviation is unknown ) , so we use t-test.

Critical value or the​ 95% confidence intervals :t_{n-1}*=2.0

Formula to find the sample size :

n=(\dfrac{t^*\cdot s}{E})^2

a) E = 5

n=(\dfrac{(2)\cdot 22.82}{5})^2

n=(9.128)^2=83.320384\approx84

i.e. Required sample size : n= 84

b)  E = 1

n=(\dfrac{(2)\cdot 22.82}{1})^2

n=(45.64)^2=2083.0096\approx2084

i.e. Required sample size : n= 2084

8 0
3 years ago
The sum of two rational numbers is -8. if one of the is -8/17, find the other. plz help me ​
Vesnalui [34]
<h2>Step-by-step explanation:</h2>

-5/7 + x = -1

(-5+7x)/7 = -1

-5 + 7x = -7

7x = -2

<h2>x = -2/7</h2>

please change the digit as per ur QUESTION

6 0
3 years ago
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a purse has $8 in dimes and quarters. there ten more dimes than quarters. Find the number of each type of coin.
natita [175]
20 quarters = $5.00
30 dimes = $3.00
4 0
4 years ago
Find the missing angle measure in ΔABC.
Otrada [13]
The answer to your question is b
4 0
3 years ago
What is the completely factored form of x4 8x2 – 9?
Alinara [238K]

For this case we have the following polynomial:

x ^ 4 + 8x ^ 2 - 9

We make the following change of variables:

u = x ^ 2

Rewriting we have

u ^ 2 + 8u - 9

Factoring the second order polynomial we have:

(u + 9) (u-1)

Then, returning the change we have:

(x ^ 2 + 9) (x ^ 2-1)

Finally, we factor the expression in the parentheses of the second term:

(x ^ 2 + 9) (x + 1) (x-1)

Answer:

the completely factored form is:

(x ^ 2 + 9) (x + 1) (x-1)

7 0
3 years ago
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