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3 years ago

Let F(x)=X^2-19 and G(x)=20-X.

Mathematics

1 answer:

Alenkasestr [34]3 years ago

5 0

Answer: 17/14

Step-by-step explanation:

Given F(x) = x² - 19, G(x) = 20 - x

Then;

(F/G)(x) = F(x) / G(x) = (x² - 19) / (20 - x)

=> (F/G)(x) = (x² - 19) / (20 - x)

at x = 6, it means anywhere we see x in the function above, we should substitute 6. Therefore,

(F/G)(6) = (6² - 19) / (20 - 6) = (36 - 19) / (14) = 17/14

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Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

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In this problem, we have that:

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