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2 years ago

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A committee must be formed with 3 teachers and 3 students. If there are 10 teachers to choose from, and 9 students, how many dif

ferent ways could the committee be made?

1 answer:

erma4kov [3.2K]2 years ago

7 0

Answer:

i dont know

Step-by-step explanation:

sorry big homie on school

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3 more than a number then divided the result by 8

ziro4ka [17]

We are given statement : 3 more than a number then divided the result by 8.

We need to write an algebraic expression for it.

Let us assume unknown number be n.

3 more than n = (n+3).

Now, we need to divide that result (n+3) by 8.

So, we would get (n+3) divided by 8 = $\frac{n+3}{8}$ .

<h3>Therefore, final expression is $\frac{n+3}{8}.$ </h3>

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3 years ago

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Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini

Nat2105 [25]

By inspection, it's clear that the sequence must converge to $\dfrac32$ because

$\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32$

when $n$ is arbitrarily large.

Now, for the limit as $n\to\infty$ to be equal to $\dfrac32$ is to say that for any $\varepsilon>0$ , there exists some $N$ such that whenever $n>N$ , it follows that

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|$

From this inequality, we get

$\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}$
$\implies|2n-1|>\dfrac5{2\varepsilon}$
$\implies2n-1\dfrac5{2\varepsilon}$
$\implies n\dfrac12+\dfrac5{4\varepsilon}$

As we're considering $n\to\infty$ , we can omit the first inequality.

We can then see that choosing $N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil$ will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that $N\in\mathbb N$ .

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2 years ago

If A = (-2, -4) and B = (-8, 4), what is the length of AB?

svetoff [14.1K]

Answer: OPTION D

Step-by-step explanation:

To solve this exercise you must use the formula for calculate the distance between two points, which is shown below:

$d_{(A,B)}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Now, you must substitute the points given in the problem into the formula:

A(-2,-4)

B(-8,4)

$d_{(A,B)}=\sqrt{(-8-(-2))^2+(4-(-4))^2}$

Then, the result is:

$d_{(A,B)}=10units$

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3 years ago

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Based on the similar triangles shown below, Theodore claims that ∆TUV is transformed to ∆WXY with a scale factor of 32. Is Theod

ICE Princess25 [194]

Answer:

Yes, the triangles are simirar with a scale factor of 3/2.

Step-by-step explanation:

We find the scale factor by dividing corresponding sides:

12/8=3/2

18/12=3/2

24/16=3/2

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2 years ago

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Colt1911 [192]

Answer:

4/25 or 0.16

Step-by-step explanation:

your welcomeee

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2 years ago

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