B. four times the value of y = the value of y+9
Respuesta:
Kansas, Misuri = 8
Paradise, Michigan = 3
Explicación paso a paso:
El rango intercuartílico (IQR) = Q3 - Q1
Q3 = 3/4 (n + 1) th término
n = número de muestras
Q1 = 1/4 (n + 1) th término
Kansas Misuri:
23,25,28,28,32,33,35
Datos pedidos: 23, 25, 28, 28, 32, 33, 35
n = 7
Q1 = 1/4 * 8 = 2do trimestre = 25
Q3 = 3/4 * 8 = 6. ° tem = 33
Q1 = 33 - 25 = 8
Paradise, Michigan:
16,24,26,26,26,27,28
Datos pedidos: 16,24,26,26,26,27,28
Q1 = 1/4 * 8 = 2do = 24
Q3 =. 3/4 * 8 = 6to = 27
Q3 - Q1 = 27 - 24 = 3
Answer:
x=2y/7
Step-by-step explanation:
y=7x^1/2
7/2x=y
7/2x/7/2=y/7/2
Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
</span>
