We are given statement : 3 more than a number then divided the result by 8.
We need to write an algebraic expression for it.
Let us assume unknown number be n.
3 more than n = (n+3).
Now, we need to divide that result (n+3) by 8.
So, we would get (n+3) divided by 8 =
.
<h3>Therefore, final expression is

</h3>
By inspection, it's clear that the sequence must converge to

because

when

is arbitrarily large.
Now, for the limit as

to be equal to

is to say that for any

, there exists some

such that whenever

, it follows that

From this inequality, we get




As we're considering

, we can omit the first inequality.
We can then see that choosing

will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that

.
Answer: OPTION D
Step-by-step explanation:
To solve this exercise you must use the formula for calculate the distance between two points, which is shown below:

Now, you must substitute the points given in the problem into the formula:
A(-2,-4)
B(-8,4)

Then, the result is:

Answer:
Yes, the triangles are simirar with a scale factor of 3/2.
Step-by-step explanation:
We find the scale factor by dividing corresponding sides:
12/8=3/2
18/12=3/2
24/16=3/2
Answer:
4/25 or 0.16
Step-by-step explanation:
your welcomeee