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4 years ago

Please help me this is hard

Mathematics

2 answers:

Svetllana [295]4 years ago

6 0

10 time 8 equals 80

iren2701 [21]4 years ago

4 0

The area needs to equal 8 so you need x to be atleast 1.6. Anything over 1.6 would make the area bigger than 8 so the inequality is x>=1.6

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What's the value of x and y?

Luda [366]

Answer:

x = 55

y = 70

Step-by-step explanation:

since it's all sides are equal its an equilateral triangle

each angle of an equilateral triangle is 60°

therefore,

y - 10 = 60 => y = 60 + 10

y = 70

x + 5 = 60 => x = 60 - 5

x = 55

3 0

3 years ago

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Can y’all please help me ……

Goryan [66]

Answer:

Step-by-step explanation:

( 8 ). m∠1 = m∠ 4 = m∠ 5 = m∠6 = 52°

( 9 ). m∠ 2 = m∠ 3 = m∠ 7 = m∠ 8 = 180° - 52° = 128°

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2 years ago

How do you graph this?

Gemiola [76]

Answer:

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Step-by-step explanation:

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3 years ago

Random variables X Poisson~ ( a) ,Y Poisson ~ ( a) . X and Y are independent. If 2 1, 2 1. U =2X+ Y-1, V=2X- Y +1. Find: ) Cov (

german

By definition of covariance,

$\mathrm{Cov}(U,V)=E[(U-E[U])(V-E[V])]=E[UV-E[U]V-UE[V]+E[U]E[V]]=E[UV]-E[U]E[V]$

Since $U=2X+Y-1$ and $V=2X-Y+1$ , we have

$E[U]=2E[X]+E[Y]-1$

$E[V]=2E[X]-E[Y]+1$

$\implies E[U]E[V]=(2E[X]+E[Y]-1)(2E[X]-(E[Y]-1))=4E[X]^2-(E[Y]-1)^2=4E[X]^2-E[Y]^2+2E[Y]-1$

and

$UV=(2X+Y-1)(2X-(Y-1))=4X^2-(Y-1)^2=4X^2-Y^2+2Y-1$

$\implies E[UV]=4E[X^2]-E[Y^2]+2E[Y]-1$

Putting everything together, we have

$\mathrm{Cov}(U,V)=(4E[X^2]-E[Y^2]+2E[Y]-1)-(4E[X]^2-E[Y]^2+2E[Y]-1)$

$\mathrm{Cov}(U,V)=4(E[X^2]-E[X]^2)-(E[Y^2]-E[Y]^2)$

$\mathrm{Cov}(U,V)=4V[X]-V[Y]=4a-a=\boxed{3a}$

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4 years ago

A sports announcer can say 80 words in 1/3 minute.whatis his speaking rate in words per minute?

Hitman42 [59]

Answer:240

Step-by-step explanation:

80 divided by 1/3

6 0

4 years ago

Read 2 more answers