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asambeis [7]
3 years ago
8

Solve for x, please solve ASAP!! Due today!

Mathematics
1 answer:
Shkiper50 [21]3 years ago
7 0
2(2x-3) = x + 9


X = 5
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Complete the square to form a perfect square trinomial x^2-14x+
fiasKO [112]
Answer: x^2 - 14x + 49

Explanation:

1) Divide the coefficient of x by 2:

14 / 2 = 7

2) so you have to add 7^2 = 49

x^2 - 14x + 49

3) that trinomial is equivalent to:

=> (x - 7)^2

4) prove that using the formula (a - b)^2 = a^2 - 2ab + b^2

(x - 7)^2  = x^2 - 14x + 49

Then you have to add 49 to complete the square. and form a perfect square trinomial.
7 0
2 years ago
(no links or files) Solve this equation using the quadratic formula. This question should be solved both ways. (1) Quadratic For
meriva
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3

Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
4 0
2 years ago
Please help and view image below!!
neonofarm [45]

Answer:y=3-6-2+4=y

Step-by-step explanation:

i dont know

i just need points

4 0
1 year ago
A hobbyist is making a toy sailboat. For the triangular sail, she wants the height h (in inches)
posledela

Answer:

xx

Step-by-step explanation:

7 0
3 years ago
The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional
jolli1 [7]

Answer:

x=\frac{16}{\sqrt[3]{2}+1 }

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = \frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}

= \frac{I}{x^2}+\frac{2I}{(16-x)^2}

now Q' = 0

⇒I{-\frac{2}{x^3}}+\frac{4}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

[/tex]\frac{1}{x^3} = \frac{2}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

is the required point

5 0
2 years ago
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