The answer is $58 × 0.020 = $1.16
1.16 + $58 = 59.16
Answer:
Length of segment QV = 35 units
Step-by-step explanation:
As shown in the figure attached,
Diagonals of TQVS are perpendicular to each other. Therefore TQVS will be a kite. By the property of a kite,
"There are two pairs of the sides which are equal in measure."
Therefore, TS ≅ TQ and SV ≅QV
Since TS ≅ TQ,
3x + 2 = 29 [Given: TQ = 29 units]
3x = 29 - 2
3x = 27
x = 9
Another pair of the consecutive sides is,
SV ≅ QV ≅ (4x - 1)
By substituting the value of x,
QV = (4 × 9) - 1
= 36 - 1
= 35 units
Therefore, length of segment QV = 35 units
we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
#SPJ1
It works well to write the given angles on the diagram, then make use of the relationships for right angles and triangles.
