What are the variables in this expression?

What is the difference between secant and tangent line?

Naily [24]

Answer:

A secant line is a straight line joining two points on a function

A tangent line is a straight line that touches a function at only one point.

Step-by-step explanation:

6 0

3 years ago

Which algebraic expression is equivalent to the expression below? 25/4(5x-4/5)+29

andre [41]

Notice* No options are provided, so I will solve the expression.

Answer:

$\frac{125x+96}{4}$

Step-by-step explanation:

Step 1: Simplify $\frac{4}{5}$

Step 2: Rewriting the whole as an Equivalent Fraction

Subtracting a fraction from a whole

Rewrite the whole as a fraction using 5 as the denominator :

5x = 5x/1 = 5x * 5/5

<em>Equivalent fraction</em> : The fraction thus generated looks different but has the same value as the whole

<em>Common denominator </em>: The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

dding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

5x • 5 - (4) 25x - 4

-------------- = ---------

5 5

Step 3: Simplify 25/4

Rewriting the whole as an Equivalent Fraction :

Adding a whole to a fraction

Rewrite the whole as a fraction using 4 as the denominator :

29 = 29/1 = 29 * 4/4

Adding fractions that have a common denominator :

Adding up the two equivalent fractions

5 • (25x-4) + 29 • 4 125x + 96

--------------------------- = -----------

4 4

Final result :

125x + 96

—————————

4

___________

Terms and topics:

Dividing exponents
Polynomial roots
Nonlinear equations
Equations which are reducible to quadratic
Reducing fractions to lowest terms

7 0

2 years ago

Find the volume of each solid

krok68 [10]

Answer:

the answer is

13 cm:y

5 cm:x

2 cm:z

3 0

3 years ago

Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention

Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

$a=\frac{d^2s}{dt^2}$

Differentiate the position vector with respect to t.

$\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}$

Differentiate both sides of the obtained equation with respect to t.

$\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}$

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

$\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}$

The initial position is obtained at t=0. Substitute t=0 in the given position function.

$\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}$

8 0

1 year ago

Two things:

Eduardwww [97]

Number one is -6 and 10
Number two is -55 and 4

5 0

3 years ago