What is the perimeter of PQR with vertices P(-2, 9), Q(7, -3) R(-2, -3) in the coordinate plane?
2 answers:
Answer:

Answer:
36.
Step-by-step explanation:
The perimeter = PQ + QR + RP
= √[(-2 -7 )^2 + (9- (-3))^2)] + √[(7 - (-2))^2 + (-3 - (-3)^2)] + √((-2 -(-2)^2+(-3-9)^2)]
= √(81+144) + √81 + √144
= √225 + √81 + √144
= 15 + 9 + 12
= 36
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