What is the perimeter of PQR with vertices P(-2, 9), Q(7, -3) R(-2, -3) in the coordinate plane?

Mathematics

2 answers:

Sergio039 [100]2 years ago

6 0

Answer:

$p (perimeter) = 36$

Ket [755]2 years ago

6 0

Answer:

36.

Step-by-step explanation:

The perimeter = PQ + QR + RP

= √[(-2 -7 )^2 + (9- (-3))^2)] + √[(7 - (-2))^2 + (-3 - (-3)^2)] + √((-2 -(-2)^2+(-3-9)^2)]

= √(81+144) + √81 + √144

= √225 + √81 + √144

= 15 + 9 + 12

= 36

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