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Reptile [31]
3 years ago
9

What is the perimeter of PQR with vertices P(-2, 9), Q(7, -3) R(-2, -3) in the coordinate plane?

Mathematics
2 answers:
Sergio039 [100]3 years ago
6 0

Answer:

p (perimeter) = 36

Ket [755]3 years ago
6 0

Answer:

36.

Step-by-step explanation:

The perimeter = PQ + QR + RP

= √[(-2 -7 )^2 + (9- (-3))^2)] + √[(7 - (-2))^2 + (-3 - (-3)^2)] + √((-2 -(-2)^2+(-3-9)^2)]

= √(81+144) + √81 + √144

= √225 + √81 + √144

= 15 + 9 + 12

= 36

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No, a & b are not independent if they're mutually exclusive.

Mutually exclusive means the two events cannot occur simultaneously. So if "a" happens "b" cannot. In contrast, two events are independent if the occurrence of one has no effect on the occurrence of the other.



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Step-by-step explanation:

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Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis?
valentina_108 [34]

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A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.

So, you must look for in your graphs where the equation is going downward.

For example, in the graph attached, that happens in any interval from negative infitity to  1.5.

The vertex will help you to identify it.

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If (3-4i) (x+iy) = 3 root 5<br> show that x^2 + y^2=9/5
NNADVOKAT [17]

Answer:

the answer is 2 + i.

Step-by-step explanation:

Let the square root of 3 + 4i be x + iy.

So (x + iy) (x +iy) = 3 +4i

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Equate the real and complex terms

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=> x = 2/y

Substitute in

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=> y^4 + 4y^2 – y^2 – 4 =0

=> y^2(y^2 + 4) – 1(y^2 + 4) =0

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Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.

Therefore y = 1 and x = 2/1 = 2

The required square root of 3 + 4i is 2 + i.

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3 years ago
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