What is the perimeter of PQR with vertices P(-2, 9), Q(7, -3) R(-2, -3) in the coordinate plane?

Mathematics

2 answers:

Sergio039 [100]2 years ago

6 0

Answer:

$p (perimeter) = 36$

Ket [755]2 years ago

6 0

Answer:

36.

Step-by-step explanation:

The perimeter = PQ + QR + RP

= √[(-2 -7 )^2 + (9- (-3))^2)] + √[(7 - (-2))^2 + (-3 - (-3)^2)] + √((-2 -(-2)^2+(-3-9)^2)]

= √(81+144) + √81 + √144

= √225 + √81 + √144

= 15 + 9 + 12

= 36

You might be interested in

A container contains 12 diesel engines. The company chooses 5 engines at random, and will not ship the container if any of the

Rufina [12.5K]

Answer: $\frac{^{10}C_5}{^{12}C_5}$

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is $^{10}C_5$

no of ways in which any 5 engines are selected from a total of 12 engines is

$^{12}C_5$

Therefore the required probability = $\frac{^{10}C_5}{^{12}C_5}$

= $\frac{7}{22}$ =0.318

3 0

2 years ago

Gulf gully and jump rope road are a pretty far distance.If the scale for the map is 0.5 inches=2.3 miles,what is the actual dist

Nezavi [6.7K]

Answer:

12 cm = 21.62 miles

6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of $\frac{map}{real world}$ and simplify.

We know $\frac{map}{real world}=\frac{0.5in}{2.3 miles}$ . We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write $\frac{4.7in}{xmiles}$ and $\frac{2.4in}{xmiles}$