What is the perimeter of PQR with vertices P(-2, 9), Q(7, -3) R(-2, -3) in the coordinate plane?
2 answers:
Answer:
Answer:
36.
Step-by-step explanation:
The perimeter = PQ + QR + RP
= √[(-2 -7 )^2 + (9- (-3))^2)] + √[(7 - (-2))^2 + (-3 - (-3)^2)] + √((-2 -(-2)^2+(-3-9)^2)]
= √(81+144) + √81 + √144
= √225 + √81 + √144
= 15 + 9 + 12
= 36
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Answer: Technically, it would be 9/3, but you can simplify that to 3.
Answer:
x = 7
3x + 11 = 32
8x + 2 = 58
Step-by-step explanation:
3x + 11 + 8x + 2 = 90
11x + 13 = 90
11x = 77
x = 7
3x + 11 = 3(7) + 11 = 32
8x + 2 = 8(7) + 2 = 58
Yeah there all right but I have a little hinch for the last and first one
(3a-7)^2
1. 9a^2-21a-21a+49
2. 3a(3a-7)-7(3a-7)
3. (3a-7)(3a-7)
4. Combine like terms
To get 1/10 -> 1000/10 =100
and 1% of 100 -> 100/100 = 1 or 1%
100 for question 1
1 for q2
