The answer is 7^4/5^2 = 96.04
Answer:
Given 7b²-21b-273=7, the solutions are x1 = 8 and x2 = -5.
Step-by-step explanation:
Given 7b²-21b-273=7, first you need to equal zero. So
7b²-21b-273-7=0 ⇒ 7b²-21b-280 = 0
The secon step is to find the solutions applying Bhaskara´s formula x = (-b ± √(b²-4×a×c))/2×a
Where a=7, b= -21 and c= -280
After you identified each term, you have to replace it on the formula so....
x = (21 ± √(21² - 4×7×(-280)))/2×7 ⇒ x = (21 ± √(441 + 7840))/14 ⇒ x = (21 ± √8281)/14
Then you will obtain two values for x, called x1 = 8 and x2=-5.
we know that
the perimeter of the rectangle is equal to
where
P is the perimeter of the rectangle
W is the width of the rectangle
L s the length of the rectangle
In this problem
Substitute the values in the formula above
therefore
the answer is
the length of the longer side of the rectangle is equal to
Given: Circle X, Chords AB and CD, AB <span>≅ CD, distance from AB to X is 9.
1. Circle X
1. Given
2. AB and CD are chords of circle X
2. Given
3. </span>AB ≅ CD
<span>3. Given
4. AB is 9 units from X.
4. Given
<em>(You can combine some of these givens into one step if you want)</em>
5. AB and CD are equidistant from X.
5. </span>When ≅ chords are in the same circle, they are equidistant from the center.
6. CD is 9 units from X.
6. Substitution Property <span>■
Refer to the attached image if you need to.</span>