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andre [41]
3 years ago
6

9+x2=? And 3-x4=? I need help

Mathematics
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

9+x2=x2+9  3-x4=−x4+3

Step-by-step explanation:

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Here are the first three the last -I’m always scared to work with fractions lol

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प्रश्नावली- 13.2 1. एक तम्बू के नीचे का भाग लम्बवृत्तीय बेलनाकार तथा ऊपरी भाग शंक्वाकार है। यदि तम्बू के आधार का व्यास 14 मील बे
laiz [17]

I can't understand the meaning of question

4 0
3 years ago
A circular rug has a circular table in the middle. The diameter of the rug is 12 meters and the diameter of the table is 4 meter
Liula [17]

Answer:

100.53m² area of carpet is left after putting the table in place.

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3 years ago
The amount of time (in minutes) that a commuter train is late is a continuous random variable with the probability density funct
Maurinko [17]

Answer:

Mean waiting time = E(X) = 0 minute

Variance = Var(X) = 140

Step-by-step explanation:

f(x) = –3(25 – x²)/500 for –10 < x < +10

f(x) = (-75 + 3x²)/500 for -10 < x < 10

f(x) = (0.006x² - 0.15) for -10 < x < 10

a) The mean of a Probability distribution is given by its expected value

Mean = E(X) = Σ xᵢpᵢ

xᵢ = each variable In the sample space

pᵢ = probability of each variable In the sample space.

In integral terms,

E(X) = ∫ xf(x) dx (evaluating the integral all over the sample space; that is, for - 10 to 10)

E(X) = ∫¹⁰₋₁₀ xf(x) dx

E(X) = ∫¹⁰₋₁₀ x[0.006x² - 0.15] dx

E(X) = ∫¹⁰₋₁₀ [0.006x³ - 0.15x] dx

E(X) = [0.0015x⁴ - 0.075x²]¹⁰₋₁₀

E(X) = [0.0015(10⁴) - 0.075(10²)] - [0.0015(-10⁴) - 0.075(-10²)]

E(X) = [15 - 7.5] - [15 - 7.5] = 0 minutes

b) Variance is given as

Variance = Var(X) = Σx²p − μ²

where μ = mean = E(X)

In integral terms,

Var(X) = [∫¹⁰₋₁₀ x²f(x) dx] - μ²

∫¹⁰₋₁₀ x²f(x) dx = ∫¹⁰₋₁₀ x²(0.006x² - 0.15) dx

= ∫¹⁰₋₁₀ (0.006x⁴ - 0.15x²) dx

= [0.0012x⁵ - 0.05x³]¹⁰₋₁₀

= [0.0012(10⁵) - 0.05(10³)] - [0.0012(-10⁵) - 0.05(-10³)]

= [120 - 50] - [-120 + 50]

= 70 + 70 = 140

Var(X) = [∫¹⁰₋₁₀ x²f(x) dx] - μ²

Var(X) = 140 - 0² = 140.

Hope this Helps!!!

8 0
3 years ago
What is the least number of cuts you would need to make to cut a 3 by 3 by 3 inch block of cheese into 1 by 1 by 1 inch blocks o
Semenov [28]

Answer:

6 Cut Minimum

Step-by-step explanation:

According to the Question,

You have a 3x3x3 cube.

  1. First make two cuts parallel to base of the cube each at a distance of 1 unit . This leaves you with three cuboids of dimensions 3x3x1.
  2. Now make two parallel cuts parallel to the height of the cube. This leaves you with nine cuboids of dimensions 3x1x1.
  3. Now make the final two cuts each 1 unit apart parallel to width and you are left with 27 cubes of 1x1x1.

So , the final answer is 6 cuts.

5 0
3 years ago
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