Pls Help. No fake answers. I need this Done soon, and I am willing to give brainlist to someone who does all of them.
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All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.
Option B contain the expression where you can see perfect square. Thus, equation (choice B) reveals its extreme value without needing to be altered.
To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:
The extreme value of this equation has a minimum at the point (2,5).
Answer:
Shortest distance from A to C = 102.9005 m.
Step-by-step explanation:
It is given that, ABCD is a rectangular park.
The length of the park is 80 m.
The breadth of the park is 50 m.
The diameter of the circle = 15 m.
We have to calculate the shortest distance from A to C across the park.
The distance AC = = 94.339 m.
As one has to pass only through the lines shown, he cannot pass through the circle.
So, we have to subtract the diameter of 15 m from AC
=> 94.339 m - 15 m = 79.339 m.
One must pass through either half of the circumference of the circle.
Since, diameter of circle = 15 m, its radius(r) = = 7.5 m.
The circumference of the circle = 2×π×r = 47.123 m.
Half of the circumference = = 23.5615 m.
Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.
As we have to calculate the shortest distance from A to C, one cannot pass from A to C either through B or D,
since the distance ABC or ADC = 50+80 = 130 m.
Therefore, shortest distance from A to C = 102.9005 m.