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Genrish500 [490]
3 years ago
7

Select the correct answer from each drop-down menu.

Mathematics
2 answers:
Annette [7]3 years ago
7 0

All of given options contain quadratic functions. One way to determine the extreme value is squaring the expression with variable x.

Option B contain the expression where you can see perfect square. Thus, equation \bf{y=-(x-2)^2+5} (choice B) reveals its extreme value without needing to be altered.

To determine the extreme value of this equation, you should substitute x=2 (x-value that makes expression in brackets equal to zero) into the function notation:

y=-(2-2)^2+5=5.

The extreme value of this equation has a minimum at the point (2,5).

Fed [463]3 years ago
4 0
Equation d since the coefficient of the quadratic term is negative
(2,-4)
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