Question

ABCD Is a rectangle that represents a park.

Answer 1

Answer:

Step-by-step explanation:

circumference of circle = 47.12m

47.12m / 2 = 23.56m

80m²+50m²= 8900m

√8900m = 94.34m

94.34m - 15m = 79.34m

79.34m + 23.56m = 102.90 m

Answer 2

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = $\sqrt{50^{2}+80^{2} }$ = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = $\frac{15}{2}$ = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = $\frac{47.123}{2}$ = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass  from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.