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ss7ja [257]
4 years ago
15

I need help with this. ASAP

Mathematics
2 answers:
Ann [662]4 years ago
5 0
4000 is the correct answer
Margaret [11]4 years ago
4 0
The answer in 4,000.
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For any real number c, √² =<br> A. ²<br> B. cl<br> C. 1<br> D. C
aliina [53]

Answer:

answer D    ( if i interpreted your question correctly )

Step-by-step explanation:

Sqrt (c^2)  = √(c^2) = C

8 0
2 years ago
Prove that the limit x tends to 1 (2x^4-6x^3+x^2+3)÷(x-1)=-8
elixir [45]
First note that if x\neq1, you have

\dfrac{2x^4-6x^3+x^2+3}{x-1}=2x^3-4x^2-3x-3

Now, you're looking for \delta>0 such that for any \varepsilon>0, you have

|x-1|

Note that you can divide through the left side of the \varepsilon inequality by x-1 once more:

\dfrac{2x^3-4x^2-3x+5}{x-1}=2x^3-2x-5\implies 2x^3-4x^2-3x+5=(x-1)(2x^2-2x-5)

So it follows that you need to find an appropriate \delta that will guarantee

|(x-1)(2x^2-2x-5)|=|x-1||2x^2-2-5|

For the moment, let's fix \delta=1. Then by this assumption, we have

|x-1|

From this we get

\implies0
\implies0
\implies0
\implies-5
\implies1

where the upper bound is what we care about. With this assumption, we then get that

|x-1||2x^2-2-5|

which suggests that \delta can be taken to be either the smaller of 1 or \dfrac{\varepsilon}5, or \delta=\min\left\{\dfrac{\varepsilon}5,1\right\}, to guarantee that the function gets arbitrarily close to -8.
5 0
3 years ago
The volume of a rectangular prism can be found by multiplying the base area, B, times the height. If the volume of the prism is
Drupady [299]
If you really meant that the height is x^2, then the area of the base is 

15x^2 + x + 2
------------------ .
         x^2

If you perform this division, you'll obtain 15 + (x+2)/(x^2).

So, again, verify your representation of the height of the prism.

3 0
4 years ago
Read 2 more answers
Is 2/10 the same as 20/100
kati45 [8]

Answer:

yes

Step-by-step explanation:

2/10 times 10 equals 20/100

4 0
3 years ago
1)Shannon takes a class to learn Japanese.The class costs $243 and lasts for 12 weeks.what is the cost,per week,of the Japanese
miskamm [114]
243 divided by 12 is $20.25
5 0
3 years ago
Read 2 more answers
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