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Natasha2012 [34]
3 years ago
8

Find the domain of the graphed function​

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

2greater then or equal to x 5 greater then or equal to

zepelin [54]3 years ago
4 0

Answer:2 < x < 5

Step-by-step explanation:

I should look like this but with lines under the less than symbol

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The length of a rectangle is 3 less than 2 times its width. The area of the rectangle is 77 squared feet.
larisa86 [58]

Answer:

Let the Width(W) =X feet

then Length(L) = (2X-3)feet

Area of the rectangle (A)=77 square feet

A = L× W

L×W=A

(2X-3) × X = 77

2X²- 3X =77

2X²-3X -77=0

Solving it using the factorization method

2X²-14X+11X-77=0

(2X²-14X)+(11X-77)=0

2X(X-7) + 11(X-7)=0

(2X+11)(X-7) =0

When 2X+11=0

X= -11/2

When X-7=0

X = 7

Therefore X= 7

Width = X feet

= 7feet

The width is 7feet

Length = (2X-3)feet

= (2×7) -3)feet

=(14-3)feet

=11feet

3 0
3 years ago
Y^3-9y^2+y-9 I don't know how to solve this can you help
aleksley [76]
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?

In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.

So you're final answer should be y = i and 9
3 0
3 years ago
the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons
padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

\dfrac{11}{16} +  \dfrac{1}{64}

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

\dfrac{11*4}{16*4} +  \dfrac{1}{64}

\dfrac{11*4}{16*4} +  \dfrac{1}{64} Which results in

\dfrac{44}{64} +  \dfrac{1}{64}

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

\dfrac{11}{16} - \dfrac{1}{64}

Your answer should be 3 and 43/64


4 0
3 years ago
Aidan rollerblades 540 ft per min. at this rate how far in yards will he rollerblade in 5 min( 1 yd =3 ft)​
Pani-rosa [81]

Answer:

900 yards

Step-by-step explanation:

540/3=180

180x5=900

6 0
3 years ago
HELP WITH 4,5 AND 6 PLZZ
Blababa [14]

Answer:

4) divide, 5) multiply, 5) divide

Step-by-step explanation:

4) you need to divide to determine the length each individual ribbon will be

5) you need to multiply the price of one shirt by three to find the price of three shirts

6) you need to divide the amount of dog food the dog will eat each day by the amount of dog food to see how many days the food will last.

6 0
3 years ago
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