Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
With what if you uploaded someone it isn’t loading for me
Step-by-step explanation:
![f(x) = \sqrt[3]{x - 3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%20-%203%7D)
The domain of a function are the values of 
that you can plug into the function 
.
Values inside of a root must be non-negative, which means that 
must be greater than or equal to zero. We can set up an equation to find the domain:
With this, we know the domain of the function is 
.
The range of a function are the values that can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is 
.
