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meriva
2 years ago
5

Solve the binomial (3x-2)^2​

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
3 0

Answer:

x=2/3  double zero

Step-by-step explanation:

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Simplify &gt;&gt;&gt;&gt;&gt;&gt;&gt; <br><br><br> 2(4x+9)
Black_prince [1.1K]

2(4x+9)

mutiply the bracket by 2

(2)(4x)= 8x

(2)(9)= 18

Answer: 8x+18

8 0
3 years ago
Javier is building a model train. He has enough track for a train that is
Musya8 [376]
He doesn’t have enough for both to be on at a time but if the cars are on without the train the cars will take up 2.4 meters leaving them with an extra .1 meters of length
5 0
2 years ago
Find a1, for the arithmetic series<br> with S14 = - 420 and d = -6.
faust18 [17]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} n = 14\\ d= -6 \end{cases} \\\\\\ a_{14}=a_1+(14-1)(-6)\implies a_{14}=a_1+(13)(-6)\implies a_{14}=a_1-78 \\\\[-0.35em] ~\dotfill

\bf \textit{sum of a finite arithmetic sequence} \\\\ S_n=\cfrac{n(a_1+a_n)}{2}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{last term's}\\ \qquad position\\ a_1=\textit{first term}\\ \cline{1-1} n= 14\\ S_{14}=-420\\ a_{14}=a_1-78 \end{cases}\implies S_{14}=\cfrac{n(a_1+a_{14})}{2} \\\\\\ -420=\cfrac{14[a_1+(a_1-78)]}{2}\implies -420=7(2a_1-78)\implies \cfrac{-420}{7}=2a_1-78 \\\\\\ -60=2a_1-78\implies 18=2a_1\implies \cfrac{18}{2}=a_1\implies 9=a_1

8 0
3 years ago
A Web music store offers two versions of a popular song. The size of the standard version is 2.1 megabytes (MB). The size of the
fiasKO [112]

Answer:

H=310

Step-by-step explanation:

This problem is a great systems of equations problem--you have two different variables: song size and number of songs.

Let's call the number of standard version downloads (S) and the high quality downloads (H).

You can make two statements:

For number of songs downloaded: S + H = 910

For download size: 2.8(S) + 4.4(H) = 3044.

S will be the same number in both equations and H will be the same number in both equations, so to find S, we can rearrange the first statement to H = 910 - S, then substitute or plug in (910 - S) wherever you see an H in the second equation so that you have only S's in your equation. Should look like this:

2.8(S) + 4.4(910 - S) = 3044

2.8S + 4004 - 4.4S = 3044

-1.6S = -960

s = 600

Your question only asks for the standard version downloads, but to help you out in future Systems situations-

You can also solve for H once you have S by plugging it into either of your equations like this:

600 + H = 910

-600

Hope this helps!

7 0
2 years ago
Bob frosted 4 1/2 cakes in 3/4 of an hour. at what rate in cakes per hour did he frost the cakes?
siniylev [52]

Answer:

6 cakes an hour

Step-by-step explanation:

4 1/2=4.50

3/4= 0.75

4.50*0.75=6

7 0
3 years ago
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