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yanalaym [24]
3 years ago
5

Help help help read the image please

Mathematics
2 answers:
Liula [17]3 years ago
6 0
All it’s asking is how many students basically scored 90 and under. there’s a total of 25 kids and 14 scored a 90 or less.
Anastasy [175]3 years ago
5 0
It’s only asking how many of them scored under 90 or over 90
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Which of the following are the coordinates of the vertex of Y=3x2 + 3?
Lemur [1.5K]

Answer:

(0,3)

Step-by-step explanation:

y = 3x^2 +3

This is in the form

y = a(x-h)^2 +k

Where the vertex is (h,k)

y = 3(x-0)^2 +3

The vertex is (0,3)

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4 years ago
What digit is in the ones place of the 357th even number?
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In the pet show, 3/8 of the pets are dogs.Of the dogs, have long hair.what fraction of the pets are dogs with long hair
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How many dogs have long hair?
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4 years ago
many elevators have a capacity of 2000 pounds, if a child averages 50 pounds and an adult averages 150 pounds, write an inequali
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50x  +  150y = 2000
3 0
3 years ago
Quadratic Equation Applications
serious [3.7K]

The number of $0.50 increases to maximize the profit is X = 1.

First of all, we need to write the linear function which represents the price of the ticket for each increase of $0.50:

P - Price of each ticket.

x - number of increases.

We know that the current price is $5.00, so:

    P(x) = 0.5x + 5.00

After that, let's build a linear function which shows the number of tickets sold <u>for each</u> price increase:

    T - number of tickets.

    x - number of increases.  

    T(x) = -100x + 1200

With all this done, we can finally build the quadratic function which represents the money earned:

M - money earned

M = Tickets Sold \times TicketPrice\\\\M = T(x) \times P(x)\\\\M = (0.5x + 5) \times (-100x + 1200)\\\\M = -50x^{2}  + 600x -500x + 6000\\\\M(x) = -50x^{2}  + 100x + 6000\\\\

Now, to finish, we only have to <u>calculate the value of X</u>(number of increases) which can give us the maximum value of this function:

the X coordinate for the maximum value of a quadratic is expressed by:

   Xmax = \frac{-b}{2a} \\\\

In our equation, b = 100 and a = - 50 :

Xmax = \frac{-(100)}{2(-50)} \\\\Xmax = \frac{-100}{-100} \\\\Xmax = 1

Thus, the number of increases which <u>maximizes</u> the profit is 1.

Learn more about linear and quadratic functions in: brainly.com/question/4119784

3 0
3 years ago
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