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Viefleur [7K]
3 years ago
15

Given that 2^A×3^B×5^13=20^D×18^12, where A,B, and D are postive integers, compute A+B+D.

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer: 75

<u>Step-by-step explanation:</u>

    2^A3^B5^{13}=20^D18^{12}

⇒ 2^A3^B5^{13}=(2^2\cdot5^1)^D(2^1\cdot3^2)^{12}

⇒ 2^A3^B5^{13}=(2^{2D}\cdot5^D)(2^{12}\cdot3^{24})

⇒ 2^A3^B5^{13}=2^{2D+12}\cdot3^{24}\cdot5^D

Now compare the like bases:

2^A=2^{2D+12} ⇒ A = 2D + 12

3^B=3^{24} ⇒ B = 24

5^{13}=5^D ⇒ D = 13

Next, let's solve for A:

A = 2D + 12

  = 2(13) + 12

  = 26 + 12

  = 38

LAST STEP: Find the sum of A, B, and D

S = A + B + D

  = 38 + 24 + 13

  = 75



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