Answer:
Lee has 19 nickels and 8 dimes
Step-by-step explanation:
hello, I think I can help you with this
Step 1
Let
value of a nickel=$0.05
value of a dime=$0.10
number of nickels=N
number of nickels=D
According to the question data Lee has $1.75 in dimes and nickels.
0.05N+0.1D=1.75,equation(1)
also, the number of nickels is 11 more than the number of dimes.mathematical speaking
N=11+D,equation(2)
Step 2
replace N from equation (2) into equation (1)
0.05N+0.1D=1.75
0.05(11+D)+0.1D=1.75
Now, solve for D
0.55+0.05D+0.1D=1.75
0.15D=1.75-0.55
D=1.2/0.15
D=8
Step 3
replace the value of D into equation(2) to obtain N
N=11+8
N=11+8
N=19
Hence, Lee has 19 nickels and 8 dimes
Have a great day.
Answer:
a) -1.25
b) 0.2112
c) -1.96
Step-by-step explanation:
Data provided in the question:
Sample size, n = 400
H0 : p = 20
= 175
Now,
a) The test statistic is given as:
Z = 
on substituting the respective values, we get
Z = 
= -1.25
b) The p-value = 2 × P(Z <-1.25)
Now from the standard normal table
P(Z <-1.25) = 10.56% = 0.1056
Thus,
p-value = 2 × 1056 = 0.2112
c) for a = 0.05,
the critical value is 
i.e 
Now from standard normal table
= -1.96
X+2 =0
x= -2
subs x= -2 in the equation
(-2)^3 - k(-2)^2 +3(-2) +7k = 0
-8 - 4k - 6 +7k =0
3k = 14
k= 14/3
