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nika2105 [10]
3 years ago
6

What is the length of the diagonal of a rectangle that is 12 inches long and 6 inches wide?​

Mathematics
1 answer:
lakkis [162]3 years ago
4 0
To find the diagonal of the rectangle we have to use Pythagorean theorem!

Pythagorean theorem is used to find the length of a missing angle such as the hypotenuse or the sides a and b.

Steps to solve:

1. 12 in is the length or the base of the right triangle, and 6 in is the wide or the side a.
2. Now use the formula: a^2+b^2=c^2, and plug in the numbers!
3. 6^2+12^2=c^2, now just solve the squared numbers.
4. 36+144=c^2
5. 180=c^2
6. Find the square root of 180.

And that is you answer!
If helped mark me the brainiest!!
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The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2
serg [7]
Ya, calculus and related rates, such fun!




everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

base=db/dt

alright

area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b

so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min

therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt

the base is decreasing at 1.6cm/min
4 0
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Step-by-step explanation:

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It is given that the rectangles in the figure are similar.

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So, we get,

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i.e. 2x=12

i.e. x = 6.

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