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Ivenika [448]
3 years ago
15

The approximate number of Calories, C , that an animal needs each day is given by C=72m^3/4 , where m is the animal's mass in ki

lograms. Find the number of Calories that a 16 kilogram dog needs each day.
Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

576 Calories a 16 kilogram dog needs each day.

Step-by-step explanation:

The approximate number of Calories, C , that an animal needs each day is given by C=72m^{3/4} ,

where m is the animal's mass in kilograms.

now we find the number of Calories that a 16 kilogram dog needs each day.

we are given with m=16

So plug in 16 for m in the given equation

C=72m^{3/4}\\C=72(16)^{3/4}\\C=72(2^4)^{3/4}\\C=72(2^3)\\C= 576

576 Calories a 16 kilogram dog needs each day.

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Suppose a and b are both non zero real numbers. Find real numbers c and d such that 1/a+ib= c+id
Thepotemich [5.8K]

\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

Explanation

\frac{1}{a+bi}=c+di

Step 1

multiplicate by the conjugate

\begin{gathered} \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(bi)^2} \\ \frac{1}{a+bi}\cdot\frac{a-bi}{a+bi}=\frac{a-bi}{(a+bi)(a-bi)}=\frac{a-bi}{a^2-(-b^2)}=\frac{a-bi}{a^2+b^2} \end{gathered}

notice that

\begin{gathered} \frac{1}{a+bi}=\frac{a-bi}{a^2+b^2}=\frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i \\ \frac{a}{a^2+b^2}-\frac{b}{a^2+b^2}i=c+di \\ so \\  \end{gathered}\begin{gathered} c=\frac{a}{a^2+b^2} \\ d=\frac{-b}{a^2+b^2} \end{gathered}

I hope this helsp you

6 0
1 year ago
A pizza stand offer both hand- tossed and pan pizza. customer can add any combination of the six available topping.
photoshop1234 [79]
The correct choice would be 128.

If there are 6 options and the person can pick any number of toppings, we need to know the number of subsets that can be formed with 6. That would be 2^6 or 64.

Since there is a pan or hand-tossed option, we need to multiply 64 by 2 to find the total.
64 x 2 = 128
8 0
3 years ago
Fiona and Camilla took a load of peaches to the farmer’s market. During the first hour, they sold ½ of the peaches plus ½ of a p
Lana71 [14]
<em>They took 101 peaches to market.</em>

<u>Check:</u>

In the 1st hour, they sold (101/2 + 1/2) = 102/2 = 51.  They had 50 left.

In the 2nd hour, they sold (50/3 + 1/3)=51/3=17.  They had (50-17)=33 left.

In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9.  They had (33-9) = 24 left.

In the final hour, they sold (24/5 + 1/5) = 25/5 = 5.  They had (24-5) = 19 left.  yay!

Fiona and Camilla took their 19 remaining peaches and went home.  Sharing with
their parents and their brother Rowlf, each person had 3.8 peaches for dinner.
There was a lot of activity in the bathroom overnight.

================================================

The key to solving this one is to work it backwards.

-- They had 19 peaches left at the end of the day.

-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .

-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .

Do the same for the 2nd hour.

Then do the same for the 1st hour.

And you'll work your way back up to 101 peaches.


4 0
3 years ago
Who is Lonely at the current moment....and not busy?
sergejj [24]

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5 0
2 years ago
Help Please!!<br> What is the value of a?<br><br> Enter your answer in the box.<br><br> a =
Talja [164]

Answer:

a=15

Step-by-step explanation:

By pythagoras' theorem

25²=20²+a²

625=400+a² group like terms

a²=625-400

a²=225

\sqrt{a {}^{2} }  =  \sqrt{225}

therefore a=15

6 0
3 years ago
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