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3 years ago

Charlotte is running at a race of 9 km/h. What is Charlotte’s speed in m/s?

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

9,000

Step-by-step explanation:

1 km=1,000

9*1,000=9,000

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a truck rental company charges $19.95 to rent a truck plus $0.24 per mile driven. Find the cost to rent a truck and drive 188 mi

zubka84 [21]

Answer:

$65.07

Step-by-step explanation:

We know in this problem they charge a $19.95 fee plus the total number of miles.

0.24 times 188 = 42.12 that´s only for the miles then the rental fee

42.12 + 19.95= 65.07

4 0

3 years ago

THIS IS DUE IN 10 MIN!!

AVprozaik [17]

The discount is 50-14 = $36

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3 years ago

A towns population grew from 7500 people to 8210 over the span of 10 years. What is the rate of growth in people per year for th

lisov135 [29]

Answer: 71 people per year

Step-by-step explanation:

8210 - 7500 = 710

710 ÷ 10 = 71.

Rate of growth in people per year for those 10 years = 71 people per year.

7 0

2 years ago

Which of the binomials below is a factor of this trinomial?

mart [117]

Hi there! :)

Answer:

$\huge\boxed{D, x -4}$

---- Starting with: ----

x² - 10x + 24

Since we have a leading coefficient of 1, simply find two numbers that sum up to -10 and multiply into 24.

By guessing and checking, we get the numbers -6 and -4. Put these into factors:

(x - 6)(x - 4)

Therefore, a binomial present in factored form is D. x - 4

8 0

3 years ago

Read 2 more answers

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

3 years ago