$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
4x^2-9=0\implies 2^2x^2-3^2=0\implies (2x)^2-3^2=0
\\\\\\\
[(2x)-3][(2x)+3]=0\implies 
\begin{cases}
2x-3=0\\
2x=3\\
x=\frac{3}{2}\\
------\\
2x+3=0\\
2x=-3\\
x=-\frac{3}{2}
\end{cases}$

7 0

3 years ago

an 8-inch by 1-inch rectangular design is being enlarged on a photocopier by a factor of 120%. what are the new dimensions of th

gizmo_the_mogwai [7]

9.6 inches by 1.2 inches

5 0

4 years ago

Please help AGAIN PLEASE?

vagabundo [1.1K]

Answer:

C. T

Step-by-step explanation:

5 0

3 years ago

What is the scale factor from figureA to figure B

s344n2d4d5 [400]

Answer:

1/3

Step-by-step explanation:

The scale factor would be 1/3.

To get figure A to the size of figure B, we need to multipy all sides by 1/3.

33*1/3=11

15*1/3=5

3 0

3 years ago