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3 years ago

Which of the following expressions is equivalent to 3(22 + 54). Thank you for those who help me

Mathematics

2 answers:

Maslowich3 years ago

5 0

Answer:

Step-by-step explanation:

s344n2d4d5 [400]3 years ago

4 0

Answer:

3×22+3×54

as there's bracket, so c is the answer

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Hey!!! What is −6+(−12)

SSSSS [86.1K]

Answer:

-18

Step-by-step explanation:

Essentially the same as (-6) - 12

7 0

3 years ago

Read 2 more answers

While watching a football game, Jordan decided to list yardage gained as positive integers and yardage lost as negative integers

koban [17]

Answer:

There is a loss of 2 yards.

Step-by-step explanation:

To find the overall gain or loss, we add or subtract there values.

Initially, we have 0 yards.

Records 14, so 0 + 14 = 14, that is, for now a gain of 14

Then loses 7, so 14 - 7 = 7, for now a gain of 7.

Then, 7 - 9 = - 2, so in all, there is a loss of 2 yards.

3 0

3 years ago

Someone help me ASAP pleasssse

SpyIntel [72]

Answer:

A) I

Step-by-step explanation:

C is in 4th vertex and if moved 4 units it wii be in 1st vertex.

5 0

3 years ago

What is the simplification of (-2x+4) + 2(2x+1)

melomori [17]

(-2x+4)+2(2x+1)= -2(-x-3)

4 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago