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2 years ago

Which of the following expressions is equivalent to 3(22 + 54). Thank you for those who help me

Mathematics

2 answers:

Maslowich2 years ago

5 0

Answer:

Step-by-step explanation:

s344n2d4d5 [400]2 years ago

4 0

Answer:

3×22+3×54

as there's bracket, so c is the answer

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There are 12 inches in a foot. Find the number of inches in 6 feet

Scrat [10]

Answer:

72 inches

Step-by-step explanation:

12 × 6 = 72

Answer: There are 72 inches in 6 feet

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2 years ago

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According to the table, which ordered pair is a local minimum of the function, f(x)?

sveticcg [70]

Answer:

Option D

Step-by-step explanation:

Given is a table which gives the order pair of x and y for a function f(x)

We have to find the local minimum of the function f(x)

We have from the table the values of different f(x)

Of all we find the least value is -15 and for this x value is -2 or +2

Hence f(x) has minimum at two points

(-2,-15) and (2,-15)

Out of 4 options given we find that (2,-15) appears in IV option

Hence option D is right answer

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3 years ago

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Guy is reading a science fiction book that is 558 pages long.If he reads 28 pages each day,how many days will it take him to rea

Citrus2011 [14]

Answer:

no more than 20 days

Step-by-step explanation:

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2 years ago

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A cylinder has a base with a diameter of 6 cm, and a height of 12 cm. What is its volume?

WITCHER [35]

Answer:

V≈339.29cm³

Step-by-step explanation:

4 0

2 years ago

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

3 years ago