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Illusion [34]
3 years ago
13

5. 12.8 ft 9 ft 9 ft

Mathematics
2 answers:
user100 [1]3 years ago
7 0

Answer:

9 x 9 = <em>81</em>

9 x 12.8 x 1/2 (basically just dividing by 2) = 57.6(area of 1 triangle),                     57.6 x 4(there are 4 sides of triangles) = <em>230.4</em>

Let's add all the given areas:

81 + 230.4 = 311.4 ft^2

kykrilka [37]3 years ago
3 0

Answer:

what do we have to solve? surface area? volume?

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Find the greatest common factor of these three expressions. 5v2 , 14v4 , and 35
a_sh-v [17]

Question

Find the greatest common factor of these three expressions. 5v2 , 14v4 , and 35


Answer:

<h2>1</h2>

Step-by-step explanation:

assuming that 5v2 is 5², and 14v4 is 14^4

5² = 25

14^4 = 38416

35 = 35

The factors of 25 are: 1, 5, 25

The factors of 35 are: 1, 5, 7, 35

The factors of 38416 are: 1, 2, 4, 7, 8, 14, 16, 28, 49, 56, 98, 112, 196, 343, 392, 686, 784, 1372, 2401, 2744, 4802, 5488, 9604, 19208, 38416

--------------

the greatest common factor is 1



6 0
3 years ago
Change to an improper fraction 4 2/3=
barxatty [35]
Solutions 

To solve the problem the first step is to m<span>ultiply the whole number by the fraction's denominator (4 x 3).Add the numerator (2) to the product. 

4 * 3 = 12 

12 + 2 = 14 

= 14/3 </span>
4 0
3 years ago
Read 2 more answers
PLEASE HELP... Students are making necklaces of six beads for their mothers. There are
nasty-shy [4]

Answer:

Step-by-step explanation:

#1 Number of ways picking 2 from 6 = 6C2 = 15

#2 Arranging them in a circle (consider 1 pair AB)

can be done

1,5  (ABBBBB)   or (5,1)

2,4 ( AABBBB) or (4,2)

3,3

1,1 (ABABAB)

all up = 7 ways

#3 = product of #1 and #2 = 15x7 = 105

3 0
1 year ago
HELP!!!
marusya05 [52]
The equation of an ellipse is x²/a²  + y²/b² =1

a being the distance between the center & x intercept =7
b being the distance between the center & y intercept =5

Hence the equation of this ellipse is:

x²/49 + y²/25 =1
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3 years ago
ASAP! what numbers round to 756,000 using 2,5,5,8,6, and 2?
ioda
655,822


Please give brainliest
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