Compound interest formula = a=P(1+r/n)^nt
P= lump sum to deposit (solving for)
A= amount accumulated over the entire time (20000)
n= number of times interest is compounded annually (1)
r= rate of interest (0.82)
T= total number of years (15)
20000=P(1+0.082/1)^1*15
20000=P(1.082)^15
20000=P(3.26143638)
20000/3.26143638=P
P=$6132.2674
Actually, this answer would be true. Why?
The first equation is: a(sub <em>n</em>) = 8, 13, 18, 23
The second is: a(sub 1)=8 ; a(sub <em>n</em>)= a(sub <em>n</em>-1)+5
if you wish to find the second term, plug two into the equation for <em /><em>n</em>
8+5=13
to find the third, plug the second term, 13, in for <em>n.</em>
13+5=18.
Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!
Answer:
is a sas theorem.
Step-by-step explanation:
The answer is A i hope this helps
A,C,B
A’s unit rate is 11.0667
C’s unit rate is 12.009
B’s unit rate is 12.5
